Major math crisis here PLEASE HELP!!!!!!!!

[Artist4Jesus89]

I NEED MAJOR HELP WITH LITERAL EQUATIONS IM WAY BEHIND IN MATH CAN SOMONE HELP?!
Solve for h.
A = h/2 (b + c) i dont get it can someone please explain?!?!

[Icarus]

I NEED MAJOR HELP WITH LITERAL EQUATIONS IM WAY BEHIND IN MATH CAN SOMONE HELP?!
Solve for h.
A = h/2 (b + c) i dont get it can someone please explain?!?!

Is that A = (h/2) (b+c) or A= h(2(b+c)) ?

Whicheve it is, what you need to do is manipulate it until you have h by itself on one side. You use arithematic to slowly move everything to the other side of the equation.

Say you had

X = (25*Y)/Z +18

and you had to solve for Y. First, you would add (-18) to both sides:

X - 18 =(25*Y)/Z

(X-18)*Z = 25Y

[ (X-18)*Z ]/25 = Y

[Artist4Jesus89]

thanks

[Icarus]

Almost anything before writing a paper.

Which is to say, you're welcome.

[Syaoran]

Dose this help you out
A=(h/2)(b+c)
A/(b+c)=h/2
h=2(A/(b+c))

I Manipulated it untill I solved for h. when it says solve for h or a or what ever it is lets say x for now. you have to make that letter by its self.
For Eg.
solve for x

2(x+3)+2(y-2)=3(x-2)
2x+6+2y-4=3x-6
2x+2y+2=3x-6
2x+2y=3x-6-2
2x+2y=3x-8
2x-3x+2y=-8
-x+2y=-8
-x=-2y-8
(-x=-2y-8)/-1
x=2y+8

I hope that this helps you out.

[Artist4Jesus89]

Thank you it does help

[lostlamb99]

Wait You said Solve for h right?
So if this is the equation: A = h/2 (b + c)
Hmmm! If I recall My Algebra from last Year I think this is how you solve it:
Say you give a value for the other Variables like
A= 18, b= 8, and c= 4
so In order to answer this you have to substitute the value of the other variables.
18= h/2 (8 + 4)
18= h/2 (12)
18= 12h/2
18= 6h
18/6 = 6h/6
h= 3
Let's Check:
18= 2/2 (8+4)
18= 3/2 (12)
18= 18
so I hope this helps. ^_^